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EFFICIENCY IS INVERSLY PROPORTIONAL WITH THE DURATION (DAYS, HOURS, ETC.)
E α 1/D
E D = CONSTANT
E1 × D1 = E2 × D2
Q1. |
Seeta can complete a work in 45 days. Geeta is 25% more efficient than Seeta. In how many days can they together complete the work? |
A. 36 |
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B. 40 |
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C. 20 |
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D. 48 |
Geeta is 25% more efficient than Seeta
Let the efficiency of Seeta = 4
Efficiency of Geeta = 5
E1D1 = E2D2
4 * 45 = ( 4 + 5 ) * X
X = 20
Q2. |
Aryan can complete a piece of work in 9 days. Arav is 25% less efficient than Arav. In how many days can Arav complete the work alone? |
A. 24 |
|
B. 18 |
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C. 36 |
|
D. 12 |
Aryan can complete a piece of work in 9 days. Arav is 25% less efficient than Arav
Let the efficiency of Aryan = 4
Efficiency of Arav = 3
4 * 9 = 3 * x
x = 12
Q3. |
Karan can complete a piece of work in 30 days. Rajan is 50% more efficient than Karan. In how many days can Rajan complete the work? |
A. 60 |
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B. 15 |
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C. 20 |
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D. 10 |
Karan can complete a piece of work in 30 days. Rajan is 50% more efficient than Karan.
Let the efficiency of Karan = 2
Efficiency of Rajan = 3
We know, E1D1 = E2D2 (Read the concepts and watch the video of this concept)
2 × 30 = 3 × x
x = 20
Q4. |
Rajat can complete a piece of work in 40 days. Sujit is 50% as efficient as Rajat. In how many days can Sujit alone do the work? |
A. 20 |
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B. 80 |
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C. 60 |
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D. 50 |
50% efficiency means double the time required.
answer is 40 × 2 = 80 days
Q1. |
A is twice as efficient than B and together they can do the same work in as much time as C and D together. If C and D can complete the work in 20 and 30 days respectively working alone, then in how many days can A complete the work alone? |
A. 30 |
|
B. 24 |
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C. 18 |
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D. 12 |
A is twice as efficient than B and together they can do the same work in as much time as C and D together. If C and D can complete the work in 20 and 30 days
Let the total work = 60 units
C does 3 and D does 2 units per day
C & D together can complete in 60/5 = 12 days.
The efficiency ratio of A and B = 2 : 1
2 * x = (2 + 1) 12
x = 18 days
Q2. |
Omm is 50% as efficient as Shiv. Shanti is 25% less efficient than Omm. If Shiv alone can complete the work in 60 days, In how many days can they together complete the work? |
A. 36 |
|
B. 32 |
|
C. 24 |
|
D. 12 |
Omm is 50% as efficient as Shiv. Shanti is 25% less efficient than Omm.
Let the Efficiency of Shiv = 8
( Note:8 = 2*4 which are the denominator of fractions)
Efficiency of Omm = 4
Efficiency of Shanti = 3
8 * 60 = (8 + 4 + 3) * x
x = 32