Correct Option is C

Explanation:

To be divisible by 6, the numbers must be divisible by 2 & 3.

Case 1: Excluding '0' , we have 5 digits 1,2,3,4,& 5 whose sum = 15

This concludes any 5 digit numbers formed with 1,2,3,4and 5 will be divisible by 3.

Again the numbers must be even to be divisible by 2.

Numbers formed with the condition = 4 × 3 × 2 × 1 × 2 = 48

       (Last digits will be occupied by either 2 or 4)

Case 2: Including 0 and Excluding '3' , we have 5 digits 1,2,4,5. 0 whose sum = 12

This concludes any 5 digit numbers formed with 1, 2,4,5, and 0 will be divisible by 3.

Again the numbers must be even to be divisible by 2.

Last digits will be occupied by either 0,2, or 4

Keeping 0 in the end: 4 × 3 × 2 × 1 × 1 = 24

Keeping 2/4 in the end: 3 × 3 × 2 × 1 × 2 = 36

Total numbers formed = 48 + 24 + 36 = 108